#8656, "RE: Enclosure Question! Math Involved.. Is This Correct?" In response to In response to 0
"L=8" H=15" W="14.3 (Question- Length is Depth?)
The Measurement to contain 2 of these subs would obviouslly be double making the box in Width which would be 28.6"
I was thinking about seperating the subs in different chambers so should I just add a 3/4" piece of MDF at 14.3 dead even with the center of the width of the box."
1) yes, length is depth, that is going to be the distance between the front baffle (that the subs sit on) and the rear wall of the enclosure.
2) math time <thinking cap>.
8" for the depth. this stays the same because of the way you assemble the enclosure.
15" height
29.35" width (14.3x2+.75 for the divider)
now wait..assuming these are the external measurements, lets see what airspace this enclosure provides:
8" depth stays the same (because one dimention will always be the same)
15" height minus 1.5" (for the two sides at 3/4" each)=13.5
29.35 minus 2.25" (3/4" for each side, plus 3/4" fo the dividing wall)=27.1"
now we multiply those numbers of internal volume together and divide by 1728 to determine the total internal airspace for both speakers in cubic feet.
8x13.5x27.1/1728=1.7 cubic feet, or about 0.85 cubic feet per speaker. take into acount that each speakers frame and motor takes up about .2 cubic feet, and you arrive at a perfect 0.65 cubic feet of airspace per speaker. good job man